SHIP STABILITY, THEORY AND PRACTICE · VOLUME TWO · APPLIED STABILITY AND TRIM

Chapter 14 · Rolling, Turning and Synchronism

The ship in motion: how fast she rolls, how far she leans in a turn, and the one sea condition that makes the rolling grow.

Everything so far has been a still photograph: the ship upright, or listed, or trimmed, but not moving. This chapter lets her move. The GM that has been a number in a table becomes something a person on board can feel: it sets the beat of the roll, the lean in a turn, and the ship’s vulnerability to one particular kind of sea. The calculations are short; the judgement they support is not.

14.1 The rolling period

Push a ship over and let her go: she swings back through upright, out to the other side, and returns. The time for one complete swing, port to starboard and back to port, is her rolling period, T. Two facts about it matter. First, it belongs to the ship, not the sea: in still water she always rolls at the same beat. Second, the size of the roll makes no difference to the time it takes, at least for the moderate angles at which GZ = GM sin θ holds: a five degree roll and a fifteen degree roll both complete in the same T, like a pendulum. At large angles, where the GZ curve falls away from the straight line GM sin θ, the period lengthens.

Rolling period T = 2πK ÷ √(g × GM) seconds, where K is the radius of gyration in metres, GM the fluid metacentric height in metres (corrected for free surface) and g = 9.81 m/s²MCA formula sheet, September 2020
portstarboardone full roll: port to starboard and back: this time is the rolling period TThe rolling period: one complete swing, timedthe size of the roll does not change the time it takes; the ship keeps her own beatthe beat is set by two things only: how the weight is spread (K),and how hard the ship pushes back (GM)
Figure 14.1   One complete swing is the period. The beat stays the same as the rolling dies away.

14.2 K, the radius of gyration

K measures how far, on average, the ship’s weight sits from the rolling axis. It is not about how much weight there is, but where it is. Spread the same tonnes further from the axis, by winging out cargo or ballast, and K grows and the roll slows; concentrate them near the axis and the roll quickens. An ice skater does the identical trick: arms out, slow spin; arms in, fast spin. Moving weight sideways at the same height does not move G, so winging out changes K without touching GM: it is the one lever that slows the roll and costs no stability. For a merchant ship K comes out at between a third and two fifths of the beam; the IS Code estimate for MV Ninja at summer draught is K = CB with C = 0.373 + 0.023 B/d − 0.043 L/100 = 0.367, that is 8.89 m, which this chapter rounds to 8.9 m.

K, the radius of gyration: how far the weight sits from the rolling axisthe same tonnes, spread differently, roll differently: wide spread rolls slowly, tight spread rolls fastweights near the axis: small Kshort period: quick rollsweights winged out: large Klong period: slow rollsthe skater does the same trick: arms out, slow spin; arms in, fast spinwinging weights out increases K and slows the roll; GM does not change,because moving weight sideways at the same height leaves G where it wasfor most ships K is between a third and two fifths of the beam
Figure 14.2   Same tonnes, different addresses: wide spread means large K and a slow roll.
Animation 1 · Winging out: same GM, slower roll
weights amidships: K 8.9 m K 8.9 m rolling period 11.9 s GM 2.24 m (unchanged)
The two gold weights slide outboard and back while the ship rolls. As they wing out, K rises from 8.9 to 9.4 m and the roll visibly slows; the GM chip never moves, because sliding weight sideways at the same height leaves G where it was. The roll you see uses the true computed period throughout.

14.3 Stiff and tender

The formula puts GM under a square root in the bottom line: big GM, short period; small GM, long period. Seafarers have older words for the two ends of the scale. A stiff ship, loaded low with a large GM, snaps upright hard and rolls fast and jerkily: safe on paper, punishing on cargo lashings and crew. A tender ship, loaded high with a small GM, rolls slowly and lazily, hanging at the end of each swing: comfortable, and short of stability in reserve. The next two examples put numbers on both moods of the same ship.

Worked example 14.1

MV Ninja at summer draught, loaded low: K = 8.9 m, GM = 2.24 m. Find her rolling period.

T = 2π × 8.9 ÷ √(9.81 × 2.24) = 55.92 ÷ 4.688 = 11.9 seconds.

A twelve second beat: brisk, positive, a stiff and safe ship that will be hard work in a seaway.

Worked example 14.2

The same ship loaded to the same summer displacement with a tall deck cargo and her double bottom tanks empty, so that KG = 9.88 m: K = 9.4 m, GM = 0.45 m. Find the new period.

T = 2π × 9.4 ÷ √(9.81 × 0.45) = 59.06 ÷ 2.101 = 28.1 seconds.

The K barely moved; the GM collapsed, and the square root turned a twelve second roll into a twenty eight second one. A long lazy period is the feel of a small GM, and an officer who notices the ship hanging at the end of her roll is reading the GM without a calculator.

This condition would not be allowed to sail: the maximum KG table of the data booklet gives 9.64 m at 30456 t, and at KG 9.88 m the area under the GZ curve between 30 and 40 degrees is 0.017 m rad against the 0.030 m rad required. It is used here to show how a tender ship behaves.

Animation 2 · Stiff and tender, side by side at true relative speed
STIFF: GM 2.24, T 11.9 s TENDER: GM 0.45, T 28.1 s rolls completed: 0.0 rolls completed: 0.0 elapsed 0 s
Both ships roll through the same angle, played at true relative speed: while the stiff ship completes her brisk 11.9 second swings, the tender one is still hanging at the end of her 28.1 second roll. Same amplitude, very different beat: the period carries the information, not the size of the roll.
Stiff and tender: the same ship, two moodsMV Ninja at summer draught, first loaded low, then with a tall deck cargo and empty double bottoms (KG 9.88 m)STIFF: loaded lowK 8.9 m · GM 2.24 mT = 11.9 ssnaps back hard:fast, jerky, hard on crew and lashingsTENDER: deck cargo highK 9.4 m · GM 0.45 mT = 28.1 slazy and slow:comfortable, but she hangs at the end of each rollneither mood is free: the stiff ship punishes the cargo,the tender ship has little stability in reserve,and each is vulnerable to a different sea, as Section 14.5 shows
Figure 14.3   Worked examples 14.1 and 14.2: the same ship, eleven point nine seconds against twenty eight point one.
Laboratory 1 · The period machine
Defaults reproduce Worked example 14.1; set K 9.4 and GM 0.45 for Worked example 14.2. Notice the square root: halving the GM does not double the period, it multiplies it by about 1.4.

14.4 The rolling test: a stopwatch estimate of GM

The period formula runs backwards. Time the roll, assume a K, and out comes an estimate of GM. At sea this is done by timing several complete rolls and averaging, because one roll is hard to clock cleanly.

GM = (2πK ÷ T)² ÷ gMCA formula sheet, September 2020
Worked example 14.3

An officer times ten complete rolls in 126 seconds. Taking K = 8.9 m, estimate the GM.

One period T = 126 ÷ 10 = 12.6 seconds.

GM = (2π × 8.9 ÷ 12.6)² ÷ 9.81 = (55.92 ÷ 12.6)² ÷ 9.81 = 19.70 ÷ 9.81 = 2.01 m.

An estimate, not a survey: it stands on the assumed K. But it is honest enough to notice trouble, and close to the 2.24 m the ship actually had in Worked example 14.1.

The rolling test: a stopwatch estimate of GMtime several complete rolls, average them, and run the period formula backwardsten complete rolls timed126 secondsone rolling period T126 ÷ 10 = 12.6 srearranged formulaGM = (2πK ÷ T)² ÷ gwith K 8.9 m(55.92 ÷ 12.6)² ÷ 9.81 = 19.70 ÷ 9.81estimated GM2.01 man estimate, not a survey: it depends on the K assumed, but it is honest enough to notice trouble
Figure 14.4   Worked example 14.3: ten rolls, a stopwatch, and the formula run backwards.
Laboratory 2 · The rolling test estimator
Defaults reproduce Worked example 14.3. Slide the assumed K and watch the estimate move: the test is only as good as the K behind it, which is why it is a check, not a survey.

14.5 Heel in a turn

Put the wheel over and the ship is forced round a circle. The turn pushes her outward through G; the water resists roughly through B. Those two forces, separated by the vertical distance BG, form a couple that heels her outward, and the GM is what resists it. Speed enters squared: half the speed means a quarter of the heel.

Tan of the heel in a turn = v² × BG ÷ (g × radius × GM), with v in metres per second, the radius, BG = KG − KB and GM in metres, and g = 9.81 m/s²MCA formula sheet, September 2020
Worked example 14.4

MV Ninja turns at 15 knots on a 300 m radius at summer draught (KB 5.041 m, KM 10.33 m, beam 24.2 m, draught 9.60 m), first loaded low (KG 8.09 m), then tender (KG 9.88 m, GM 0.45 m). Find the heel and the under keel clearance in 12.60 m of water for each condition.

Speed: 15 knots = 7.717 m/s, so v² = 59.55.

Stiff: BG = 8.09 − 5.041 = 3.049 m, GM = 2.24 m. Tan of the heel = 59.55 × 3.049 ÷ (9.81 × 300 × 2.24) = 0.0275, heel = 1.58°, call it 1.6° outward.

Tender: BG = 9.88 − 5.041 = 4.839 m, GM = 0.45 m. Tan of the heel = 59.55 × 4.839 ÷ (9.81 × 300 × 0.45) = 0.2176, heel = 12.28°, call it 12.3°. The same wheel heels this condition nearly eight times as far (the tangents are in the ratio 7.9): the lever BG grew by a factor of 1.59 and the resistance GM shrank by a factor of 4.98, and both changes point the same way.

Maximum draught when heeled = half beam × sin of the heel + draught × cos of the heel, using the heels to two decimal places. Stiff: 12.1 × sin 1.58° + 9.60 × cos 1.58° = 0.33 + 9.60 = 9.93 m, clearance 12.60 − 9.93 = 2.67 m. Tender: 12.1 × sin 12.28° + 9.60 × cos 12.28° = 2.57 + 9.38 = 11.95 m, clearance 0.65 m.

Upright, both conditions had 3.00 m under the keel. The tender turn spent 2.35 m of it. A tender ship is turned gently, and doubly so in shallow water.

Maximum draught when heeled = half beam × sin of heel + draught × cos of heelMCA formula sheet, September 2020
centrifugal force at G, outwardwater resistance,roughly at BHeel in a turn: two forces, one couplethe turn pushes outward at G; the water pushes back at B; the gap BG is the lever, and GM is the resistancetan of the heel = v² × BG ÷ (g × radius × GM)speed enters squared: half the speed, a quarter of the heelthe heel is outward, away from the centre of the turn
Figure 14.5   The couple in a turn: outward push at G, resistance at B, and BG as the lever.
The same wheel, 15 knots, 300 m radius: two very different shipsthe stiff ship shrugs the turn off; the tender ship leans hard and eats her own under keel clearanceSTIFF (GM 2.24, BG 3.05)TENDER (GM 0.45, BG 4.84)heel in the turn1.6°12.3°maximum draught when heeled9.93 m11.95 munder keel clearance (12.60 m of water)2.67 m0.65 mmaximum draught when heeled = half beam × sin of heel + draught × cos of heeltender: 12.1 × sin 12.28° + 9.60 × cos 12.28° = 2.57 + 9.38 = 11.95 mthe upright clearance was 3.00 m; the turn spent 2.35 m of ita tender ship is turned gently, especially in shallow water
Figure 14.6   Worked example 14.4: the same wheel, 1.6 degrees against 12.3, and the clearance the tender turn spends.
Laboratory 3 · The turning machine
Water depth fixed at 12.60 m, summer draught 9.60 m. Defaults reproduce the stiff half of Worked example 14.4; switch the condition for the tender half. Try halving the speed and watch the heel fall to a quarter: speed enters squared.

14.6 Synchronism

A ship rolling among waves is a pushed swing. If the waves arrive at random compared with her beat, the pushes mostly cancel. But if the apparent period of the waves (the encounter period), the time between crests as the ship meets them, matches her natural rolling period, then every wave pushes just as she swings, and the roll grows cycle by cycle. This is synchronism, and it is the most dangerous rolling condition a ship can be in: cargo shift, structural damage, downflooding, and in the extreme, capsize.

Worked example 14.5

MV Ninja is in the loaded condition of Worked example 14.1 (natural period 11.9 seconds) with a beam sea whose apparent period is 12 seconds. Assess the situation and state the measures available.

The apparent wave period matches her natural period within a tenth of a second: this is synchronism, and the rolling will build swing on swing until something changes.

The escapes, in order of practicality at sea: alter course, which changes the apparent wave period, and an alteration towards the sea shortens it fastest; alter speed, effective whenever the sea is anywhere but exactly abeam; and as harbour options rather than seagoing ones, change the GM or wing weights out to move the natural period itself.

The pattern to carry: short seas have periods near those of stiff ships and long swell has periods near those of tender ships, so a stiff ship is most at risk in short beam seas, and a tender ship in long ones. A sea on the quarter lengthens the apparent period, which is exactly the wrong direction for a tender, long period ship.

Animation 3 · Synchronism: the pushed swing, and the escape
beam sea, apparent period 12 s: matched to her 11.9 s beat roll amplitude 3° apparent wave period 12.0 s
Play, and watch the matched waves pump the roll up swing by swing: every crest arrives just as she rolls. Then press the green button: the course alteration of 40 degrees towards the sea shortens the apparent wave period to 9.5 s, the pushes fall out of step, and the roll dies back down. Press the green button again to return to the beam sea and watch it rebuild. The 9.5 s is calculated: a 12 s wave in deep water is 224.8 m long and travels at 18.74 m/s; at 15 knots (7.717 m/s) with the sea 40 degrees forward of the beam the crests are met every 224.8 ÷ (18.74 + 7.717 × sin 40°) = 224.8 ÷ (18.74 + 4.96) = 224.8 ÷ 23.70 = 9.5 s. Head on it would be 8.5 s, and in a following sea 20.4 s.
the waves, arriving with their apparent periodthe roll, pushed at exactly its own beat, growing every swingSynchronism: the sea pushing the swing in timewhen the apparent wave period matches the natural rolling period, every wave adds to the rollstiff ships (short T)at risk in SHORT wavestender ships (long T)at risk in LONG wavessea on the quarterlengthens the apparent period: watch the tender shipthe escapealter course (towards the sea shortens the apparent period) or alter speed
Figure 14.7   The pushed swing: matched periods make every wave add to the roll, and the escapes all work by breaking the match.

Chapter 14 in five lines

The rolling period T = 2πK ÷ √(g × GM): it belongs to the ship, and the size of the roll does not change it.

K is where the weight sits: winging out slows the roll without costing any GM.

Big GM rolls fast and hard (stiff); small GM rolls slow and lazy (tender): 11.9 against 28.1 seconds on the same hull.

Heel in a turn: tan = v² × BG ÷ (g × radius × GM), outward, with speed squared; a tender ship leans hardest and spends her own under keel clearance.

Synchronism is the matched swing: break it by altering course, towards the sea for the quickest change, or altering speed.

Test yourself